Question

При каких значениях * число 4127* делится на 2,3,5,6 ?

Answer 1

на целых числах кроме 0

это я забыл как называется 1 3 5

Answer 2

To determine whether a number is divisible by 2, 3, 5, and 6, we need to check if it satisfies the divisibility rules for each of these numbers.

1. Divisibility by 2: A number is divisible by 2 if its last digit is even (i.e., it ends in 0, 2, 4, 6, or 8).

2. Divisibility by 3: A number is divisible by 3 if the sum of its digits is divisible by 3.

3. Divisibility by 5: A number is divisible by 5 if its last digit is 0 or 5.

4. Divisibility by 6: A number is divisible by 6 if it is divisible by both 2 and 3.

Let's apply these rules to the number 4127:

1. Divisibility by 2: The last digit of 4127 is 7, which is odd, so 4127 is not divisible by 2.

2. Divisibility by 3: The sum of the digits of 4127 is 4 + 1 + 2 + 7 = 14. Since 14 is not divisible by 3, 4127 is not divisible by 3.

3. Divisibility by 5: The last digit of 4127 is 7, which is not 0 or 5, so 4127 is not divisible by 5.

4. Divisibility by 6: Since 4127 is not divisible by 2 and not divisible by 3, it is also not divisible by 6.

Therefore, the number 4127 is not divisible by 2, 3, 5, or 6.