Question

1] 1 7/8 x 0,4= 2] 1 1/3x3/7 + 4/7x 1 1/3 =

Answer 1

$1) \: 1 \frac{1}{7} \times 0.4 = \frac{8}{7} \times \frac{4}{10} = \frac{16}{35}$
$2) \: \frac{11}{3} \times \frac{3}{7} + \frac{4}{7} \times \frac{11}{3} = \\ = \frac{11}{7} + \frac{44}{21} = \frac{77}{21} = \frac{11}{3}$

Answer 2

1)17/8 × 4/10 = 17/8 × 2·2/5·2 = 17/8 × 2/5 = 17·2/8·5 = 34/40 = 17·2/20·2 = 17/20 = 0.85
2)Первое действие
11/3×3/7=11×3/3×7=33/21=11/7
Второе действие
4/7×11/3=4×11/7×3=44/21
Третье действие
11/7+44/21=11×3/7×3+44/21=33/21+44/21=77/21=11/3=2 2/3

Answer 3

Let's solve the given mathematical expressions step by step:

1] $1 \frac{7}{8} \times 0.4$

To multiply a mixed number with a decimal number, we can convert the mixed number into an improper fraction and then perform the multiplication.

Step 1: Convert the mixed number $1 \frac{7}{8}$ into an improper fraction: $1 \frac{7}{8} = \frac{8 \times 1 + 7}{8} = \frac{15}{8}$

Step 2: Multiply the improper fraction by the decimal number 0.4: $\frac{15}{8} \times 0.4 = \frac{15 \times 0.4}{8} = \frac{6}{8} = \frac{3}{4}$

So, $1 \frac{7}{8} \times 0.4 = \frac{3}{4}$.

2] $1 \frac{1}{3} \times \frac{3}{7} + \frac{4}{7} \times 1 \frac{1}{3}$

Step 1: Convert the mixed numbers into improper fractions: $1 \frac{1}{3} = \frac{3 \times 1 + 1}{3} = \frac{4}{3}$ $1 \frac{1}{3} = \frac{3 \times 1 + 1}{3} = \frac{4}{3}$

Step 2: Perform the addition and multiplication: $\frac{4}{3} \times \frac{3}{7} + \frac{4}{7} \times \frac{4}{3}$

To add fractions, we need a common denominator, which is 21 in this case.

$\frac{4}{3} \times \frac{3}{7} = \frac{4 \times 3}{3 \times 7} = \frac{12}{21}$ $\frac{4}{7} \times \frac{4}{3} = \frac{4 \times 4}{7 \times 3} = \frac{16}{21}$

Now, add the two fractions:

$\frac{12}{21} + \frac{16}{21} = \frac{12 + 16}{21} = \frac{28}{21} = 1 \frac{7}{21}$

So, $1 \frac{1}{3} \times \frac{3}{7} + \frac{4}{7} \times 1 \frac{1}{3} = 1 \frac{7}{21}$.

Note: I assumed that the multiplication operation has precedence over the addition operation. If there were parentheses in the original expression, the order of operations might change.