Question

7(x+3) больше или равно 3х+1

Answer 1

Составляем неравенство: 7(х+3)≥3х+1, решаем: 7х-3х≥1-3, 4х≥-2, х≥-1/2 -ответ

Answer 2

Конечно же 7(x+3) больше чем 3x+1

7(x+3) > 3x+1
7x+21 >3x+1

Answer 3

To solve the inequality $7(x+3) \geq 3x+1$, we need to find the values of $x$ that make the statement true.

Step 1: Distribute the terms on the left side of the inequality:

$7x + 21 \geq 3x + 1$

Step 2: Move the variable terms (those with $x$) to one side and the constant terms to the other side of the inequality:

Subtract $3x$ from both sides:

$7x - 3x + 21 \geq 3x - 3x + 1$

Simplify:

$4x + 21 \geq 1$

Step 3: Move the constant term to the other side of the inequality:

Subtract 21 from both sides:

$4x \geq 1 - 21$

Simplify:

$4x \geq -20$

Step 4: Solve for $x$ by dividing both sides by 4. Note that when you divide by a negative number, the inequality sign flips:

$x \geq \frac{-20}{4}$

Simplify:

$x \geq -5$

So, the solution to the inequality is $x \geq -5$. Any value of $x$ that is greater than or equal to -5 will make the inequality true.