Question

Y = x² + 3; x =0; x =2; y=0 С решением

Answer 1

Ответ:

1)3 2) 7 3)Нет решений

Пошаговое объяснение:

1)0^2 + 3 = 3

2)2^2 + 3 = 4 + 3 = 7

3)x^2 + 3 = 0   x^2 = -3 Число во второй степени не может быть отрицательным. Нет решений.

Answer 2

To find the values of Y given the equations Y = x² + 3 and the given values of x (x = 0, x = 2, and y = 0), we substitute each value of x into the equation and calculate the corresponding value of Y.

1. For x = 0: Y = (0)² + 3 Y = 0 + 3 Y = 3

2. For x = 2: Y = (2)² + 3 Y = 4 + 3 Y = 7

So, the solutions are: When x = 0, Y = 3 When x = 2, Y = 7 When Y = 0, there is no direct solution given the equation Y = x² + 3 since the equation is not a linear one and does not have a real root for Y = 0. In this case, there are no real values of x that satisfy the equation when Y = 0.