Question

(49 2/9-25)-(11 4/7-2/3)=

Answer 1

Відповідь:(49 2/9 - 25) - ( 11 4/7 -2/3)=(416/9-25)-(86/7-2/3)=191/9-244/21=605/63=9 38/63

Answer 2

Переводим смешанные дроби в неправильные:

$(49\frac{2}{9} - 24\frac{9}{9}) - (\frac{81}{7} - \frac{2}{3}) = 13\frac{20}{63}$

1) $48\frac{11}{9} - 24\frac{9}{9} = 24\frac{2}{9}$

2) $\frac{81}{7} - \frac{2}{3} = \frac{243}{21} - \frac{14}{21} = \frac{229}{21} = 10\frac{19}{21}$

НОЗ: 21

3) $\frac{218}{9} - \frac{229}{21} = \frac{1526}{63} - \frac{687}{63} = \frac{839}{63} = 13\frac{20}{63}$

НОЗ: 63

Answer 3

To solve the expression (49 2/9 - 25) - (11 4/7 - 2/3), we need to perform the operations step by step. First, let's simplify each mixed number:

49 2/9 - 25 = (49 * 9 + 2) / 9 - (25 * 9) / 9 = (441 + 2) / 9 - 225 / 9 = 443 / 9 - 225 / 9 = (443 - 225) / 9 = 218 / 9

Similarly,

11 4/7 - 2/3 = (11 * 7 + 4) / 7 - (2 * 7) / 3 = (77 + 4) / 7 - 14 / 3 = 81 / 7 - 14 / 3

Now, let's find a common denominator for 9 and 7, which is 63 (LCM of 9 and 7).

Converting both fractions to have a common denominator of 63:

218 / 9 = (218 * 7) / (9 * 7) = 1526 / 63

(81 / 7) = (81 * 9) / (7 * 9) = 729 / 63

Now the expression becomes:

1526 / 63 - 729 / 63

To subtract these fractions, we just subtract their numerators while keeping the common denominator:

(1526 - 729) / 63 = 797 / 63

Therefore, the result of the expression (49 2/9 - 25) - (11 4/7 - 2/3) is 797 / 63.