Question

Sin^2a*tg^2a+sin^2a+1

Answer 1

Ответ:

(〖sin〗^2 a)/(1- 〖sin〗^2 a) = 〖tg〗^2 a

(〖sin〗^2 a)/( 〖cos〗^2 a) = 〖tg〗^2 a

〖tg〗^2 a=〖tg〗^2 a

Пошаговое объяснение:

Answer 2

Ответ:

Пошаговое объяснение:sin²a × sin²a/cos²a + sin²a +1 = sin³a/cos²a +

sin²a + sin²a + cos²a = sin³a/cos²a + 2sin²a + cos²a.

Answer 3

Let's simplify the expression step by step:

1. Rewrite "tg^2a" as "tan^2a" (using the standard notation for the tangent function).
2. Apply the trigonometric identity: 1 + tan^2(a) = sec^2(a), where sec(a) is the secant function.

Now, the expression becomes:

sin^2(a) * tan^2(a) + sin^2(a) + 1

Next, we can use another trigonometric identity:

tan^2(a) = sec^2(a) - 1

Substitute this back into the expression:

sin^2(a) * (sec^2(a) - 1) + sin^2(a) + 1

Now, distribute sin^2(a):

sin^2(a) * sec^2(a) - sin^2(a) + sin^2(a) + 1

Simplify the middle terms:

sin^2(a) * sec^2(a) + 1

There isn't a simple trigonometric identity to simplify this expression further, so the final simplified expression is:

sin^2(a) * sec^2(a) + 1