Question

(b-3)(b+3)-(в+2)^2=решить

Answer 1

(b-3)(b+3)-(в+2)²=b²-9-b²-4b-4=-13-4b

Для решения использовано (a+b)²=a²+2ab+b²

(a-b)*(a+b)=a²-b²

Answer 2

To solve the equation, let's simplify the expression first:

(b - 3)(b + 3) - (b + 2)^2

Expanding the square and multiplying the binomials, we get:

(b^2 - 9) - (b^2 + 4b + 4)

Now, simplify further by combining like terms:

b^2 - 9 - b^2 - 4b - 4

Combine the constants:

-9 - 4 - 4b

Simplifying further:

-13 - 4b

Now, the equation becomes:

-13 - 4b = 0

To solve for b, let's isolate the variable:

-4b = 13

Divide both sides by -4:

b = -13/4

Therefore, the solution to the equation is:

b = -13/4