Question

570·х-4700=13540 (31·550-х)·120=10200

Answer 1

Ответ:570•х-4700=13540

570•х=13540+4700

570•х=18240

х=18240:570

х=32

570•32-4700=13540

13540=13540

(31•550-х)•120=10200

(17050-х)•120=10200

17050-х=10200:120

17050-х=85

х=17050-85

х=16965

(31•550-16965)•120=10200

10200=10200

Пошаговое объяснение:

Answer 2

To solve the given equations, we need to find the value of 'x'. Let's solve each equation step-by-step:

1. 570·x - 4700 = 13540

Step 1: Add 4700 to both sides to isolate the term with 'x': 570·x = 13540 + 4700 570·x = 18240

Step 2: Divide both sides by 570 to solve for 'x': x = 18240 / 570 x ≈ 32

So, the solution for the first equation is x ≈ 32.

2. (31·550 - x)·120 = 10200

Step 1: Perform the arithmetic inside the parentheses: 31·550 - x = 17150 - x

Step 2: Multiply the result by 120 to isolate the term with 'x': 120(17150 - x) = 10200

Step 3: Distribute the multiplication: 2058000 - 120x = 10200

Step 4: Move the constant term to the other side: -120x = 10200 - 2058000 -120x = -2045800

Step 5: Divide both sides by -120 to solve for 'x': x = -2045800 / -120 x ≈ 17048.33 (rounded to 2 decimal places)

So, the solution for the second equation is x ≈ 17048.33.