Question

6-5y>3y-23-7y>5y-3x\6+1\2>x-1\3​

Answer 1

Пошаговое объяснение:

вот ответ овлулаолавл

Answer 2

To solve the inequality, let's simplify it step by step. I assume you meant:

$6 - 5y > 3y - 23 \quad \text{and} \quad 7y > 5y - 3x + \frac{6 + 1}{2} > x - \frac{1}{3}$

Step 1: Solve the first inequality: $6 - 5y > 3y - 23$

Let's first add 5y to both sides: $6 - 5y + 5y > 3y + 5y - 23$ $6 > 8y - 23$

Next, add 23 to both sides: $6 + 23 > 8y - 23 + 23$ $29 > 8y$

Finally, divide by 8 (since the coefficient of y is 8): $y < \frac{29}{8}$

Step 2: Solve the second inequality: $7y > 5y - 3x + \frac{6 + 1}{2} > x - \frac{1}{3}$

First, let's simplify the expression inside the parenthesis: $\frac{6 + 1}{2} = \frac{7}{2}$

So the inequality becomes: $7y > 5y - 3x + \frac{7}{2} > x - \frac{1}{3}$

Step 3: Now, let's isolate the x term in the middle part of the inequality:

Move 5y to the right side: $7y - 5y > -3x + \frac{7}{2} > x - \frac{1}{3}$

$2y > -3x + \frac{7}{2} > x - \frac{1}{3}$

Step 4: Now, let's isolate the x term completely:

Move $\frac{7}{2}$ to the right side: $2y - \frac{7}{2} > -3x > x - \frac{1}{3}$

Step 5: Finally, divide everything by -3 (note the change in the direction of the inequality when dividing by a negative number):

$-\frac{2y - \frac{7}{2}}{3} < x < -\frac{x - \frac{1}{3}}{3}$

Simplified inequality: $-\frac{2y}{3} + \frac{7}{6} < x < -\frac{x}{3} + \frac{1}{9}$

So, the solution to the inequality is: $y < \frac{29}{8} \quad \text{and} \quad -\frac{2y}{3} + \frac{7}{6} < x < -\frac{x}{3} + \frac{1}{9}$