Question

№1. 4 2/7 +2 3/7 - 3 4/7=?11-(2 5/9+3 2/9)=?7 6/23-(3 5\23 +1 11/23)=?№2. X+15 17/18=22 5/1837 4/15+(2 7/15-y)=38 2/15№3.215м.=? ч. 1257ме.=? км. №4.3 1/3<a/3<5a=?​

Answer 1

Ответ:

Пошаговое объяснение:

№1.

4 2/7 +2 3/7 - 3 4/7= 6 5/7 - 3 4/7 = 3 1/7

11-(2 5/9+3 2/9)= 11 - 5 7/9 = 5 2/9

7 6/23-(3 5\23 +1 11/23)= 7 6/23 - 4 16/23 = 6 29/23 - 4 16/23 = 2 13/23

№2.  

X+15 17/18=22 5/18

x = 22 5/18 - 15 17/18

x = 21 23/18 - 15 17/18

x = 6 6/18

x = 6 1/3

37 4/15+(2 7/15-y)=38 2/15

2 7/15 - y = 38 2/15 - 37 4/15

2 7/15 - y = 13/15

y = 2 7/15 - 13/15

y = 1 9/15

y = 1 3/5

№3.

215м.=? ч.  

1257ме.=? км.  

№4.

3 1/3<a/3<5

a=11;12;13;14

Answer 2

Let's solve each problem step by step:

№1:

1. 4 2/7 + 2 3/7 - 3 4/7 = (4 + 2) + (2 + 3) - (3 + 4)/7 = 6 + 5 - 7/7 = 11 - 1 = 10

2. 11 - (2 5/9 + 3 2/9) = (11 - 3) - (2 + 3)/9 = 8 - 5/9 = 8 4/9

3. 7 6/23 - (3 5/23 + 1 11/23) = 7 - 3 - 1 + (6 - 5 - 11)/23 = 3 - 10/23 = 2 13/23

№2:

1. X + 15 17/18 = 22 5/18 To solve for X, we need to subtract 15 17/18 from both sides: X = 22 5/18 - 15 17/18 X = 6 12/18 X = 6 2/3

2. 37 4/15 + (2 7/15 - y) = 38 2/15 To solve for y, we need to subtract 37 4/15 from both sides and then subtract 2 7/15 from both sides: 2 7/15 - y = 38 2/15 - 37 4/15 2 7/15 - y = 30/15 y = 2 7/15 - 2 y = 2 5/15 y = 2 1/3

№3:

1. To convert 215 meters to centimeters, we multiply by 100 (since there are 100 centimeters in a meter): 215 meters = 215 * 100 = 21,500 centimeters.

2. To convert 1257 meters to kilometers, we divide by 1000 (since there are 1000 meters in a kilometer): 1257 meters = 1257 / 1000 = 1.257 kilometers.

№4: 3 1/3 < a/3 < 5a

To solve for "a," we need to find the range of values that satisfy the inequality.

1. 3 1/3 < a/3: First, we convert the mixed number to an improper fraction: 3 1/3 = (3 * 3 + 1)/3 = 10/3 Now, multiply both sides by 3: 3 * 10/3 < a 10 < a

2. a/3 < 5a: To avoid dividing by zero, we assume a is positive. Now, we can safely divide both sides by "a": 1/3 < 5 This statement is true for any positive value of "a."

Combining the inequalities: 10 < a and 1/3 < a.

So, the range of "a" is a value greater than 10 and a positive value greater than 1/3. In interval notation, it can be expressed as (10, ∞).