Question

2‹a‹5 оценить: 2a;2/4a;-2a;2a-2;1/a​

Answer 1

Пошаговое объяснение:

2*2∠2а∠5*2 ⇒ 4∠2а∠10

2*2/4∠2/4а∠2/4*5 ⇒ 1∠0,5а∠2,5

2*(-2)∠-2а∠5*(-2) ⇒ -4⊃-2а⊃-10

2*2-2∠2а-2∠5*2-2 ⇒ 2∠2а-2∠8

1/2∠1/а∠1/5 ⇒ 0,5∠1/а∠0,2

Answer 2

To evaluate the given expressions, let's substitute the value of "a" within the given range (2‹a‹5). Here are the evaluations:

1. 2a: Substituting the minimum value of "a" (2) into the expression: 2 * 2 = 4

   Substituting the maximum value of "a" (5) into the expression: 2 * 5 = 10

   Therefore, the expression 2a evaluates to 4 when a = 2 and 10 when a = 5.

2. 2/4a: Substituting the minimum value of "a" (2) into the expression: 2 / (4 * 2) = 2 / 8 = 0.25

   Substituting the maximum value of "a" (5) into the expression: 2 / (4 * 5) = 2 / 20 = 0.1

   Therefore, the expression 2/4a evaluates to 0.25 when a = 2 and 0.1 when a = 5.

3. -2a: Substituting the minimum value of "a" (2) into the expression: -2 * 2 = -4

   Substituting the maximum value of "a" (5) into the expression: -2 * 5 = -10

   Therefore, the expression -2a evaluates to -4 when a = 2 and -10 when a = 5.

4. 2a-2: Substituting the minimum value of "a" (2) into the expression: 2 * 2 - 2 = 4 - 2 = 2

   Substituting the maximum value of "a" (5) into the expression: 2 * 5 - 2 = 10 - 2 = 8

   Therefore, the expression 2a-2 evaluates to 2 when a = 2 and 8 when a = 5.

5. 1/a: Substituting the minimum value of "a" (2) into the expression: 1 / 2 = 0.5

   Substituting the maximum value of "a" (5) into the expression: 1 / 5 = 0.2

   Therefore, the expression 1/a evaluates to 0.5 when a = 2 and 0.2 when a = 5.

I have evaluated the given expressions based on the range 2‹a‹5.