Question

(19y+32)(3 7/10-4/5y)=0

Answer 1

Ответ:

Пошаговое объяснение:

19у+32=0

19у=-32

У=-32/19

У1=-1 13/19

3 7/10-4/5у=0

4/5у=3 7/10

У=3 7/10:4/5

У=37/10*5/4

У2=37/8=4 5/8

Answer 2

To solve the equation (19y + 32)(3 7/10 - 4/5y) = 0, you need to find the values of y that make the entire expression equal to zero. To do that, set each factor equal to zero and solve for y separately:

1. Set (19y + 32) = 0: 19y + 32 = 0 19y = -32 y = -32/19

2. Set (3 7/10 - 4/5y) = 0: 3 7/10 - 4/5y = 0 4/5y = 3 7/10 y = (3 7/10) / (4/5) y = (37/10) / (4/5) y = 37/10 * 5/4 y = 37/2

So, the solutions for the equation are y = -32/19 and y = 37/2.