Question

X2+3x+2=0 D= x1= x2= 1 x2 это x во 2.

Answer 1

$x^2+3x+2=0\\D=3^2-4*2=9-8=1\\x_1=\frac{-3+\sqrt{1} }{2} =-1\\x_2=\frac{-3-\sqrt{1} }{2} =-2$

Answer 2

Ответ:

D=3^2-4×1×2=1

Корень из 1=1

x1=-3+1/2×1=-1

x2=-3-1/2×1=-2

Answer 3

It seems like you have given the quadratic equation x^2 + 3x + 2 = 0 and asked for the discriminant (D) and the solutions for x1 and x2.

The quadratic equation is in the form ax^2 + bx + c = 0, where a, b, and c are coefficients.

To find the discriminant (D), you can use the formula: D = b^2 - 4ac

In this case, a = 1, b = 3, and c = 2: D = (3)^2 - 4(1)(2) D = 9 - 8 D = 1

Now, to find the solutions for x1 and x2, you can use the quadratic formula: x = (-b ± √D) / 2a

Plugging in the values, we get: x1 = (-(3) + √1) / 2(1) x1 = (-3 + 1) / 2 x1 = -2 / 2 x1 = -1

x2 = (-(3) - √1) / 2(1) x2 = (-3 - 1) / 2 x2 = -4 / 2 x2 = -2

So the discriminant (D) is 1, and the solutions for x1 and x2 are -1 and -2, respectively.