Question

__найти |AC| если A(2;-3;-1) C(3;1;-2)​

Answer 1

Ответ:

$\sqrt{18}$

Пошаговое объяснение:

$|AC| = \sqrt{(3-2)^{2}+(1-(-3))^{2}+(-2-(-1))^{2} } = \sqrt{1+16+1}=\sqrt{18}$

Answer 2

To find the distance between points A(2, -3, -1) and C(3, 1, -2), we can use the distance formula in three-dimensional space. The distance formula is given by:

d = sqrt((x2 - x1)^2 + (y2 - y1)^2 + (z2 - z1)^2)

Substituting the coordinates of points A and C into the formula, we have:

d = sqrt((3 - 2)^2 + (1 - (-3))^2 + (-2 - (-1))^2)

Simplifying:

d = sqrt(1^2 + 4^2 + (-1)^2) d = sqrt(1 + 16 + 1) d = sqrt(18) d ≈ 4.24

Therefore, the distance between points A and C, |AC|, is approximately 4.24 units.