Question

3(х+4)-5х (х-2y)+(2х+5у) -(х-m)+m -3(y+n)-y -2(x+3)-3(2x-4

Answer 1

Ответ:

Пошаговое объяснение:

3(х+4)-5х  = 3x + 12 - 5x = -2x + 12

(х-2y)+(2х+5у)  = x - 2y + 2x + 5y = 3x + 3y

-(х-m)+m  = -x + m + m = -x + 2m

-3(y+n)-y  = -3y - 3n - y = -4y - 3n

-2(x+3)-3(2x-4) = -2x - 6 - 6x + 12 = -8x + 6

Answer 2

Ответ:

Пошаговое объяснение:

3х+12-5х=-2х+12=2(х+6)

х-2у+2х+5у=3х+3у=3(х+у)

-х+m+m=-x+2m

-2х-6-6х+12=-8х+6=2(4х+3)

Answer 3

Let's simplify the given expression step by step:

1. Distribute the numbers outside the parentheses:

   3(x + 4) - 5x(x - 2y) + (2x + 5y) - (x - m) + m - 3(y + n) - y - 2(x + 3) - 3(2x - 4)

2. Apply the distributive property inside each set of parentheses:

   3x + 12 - 5x^2 + 10xy + 2x + 5y - x + m + m - 3y - 3n - y - 2x - 6 - 6x + 12

3. Combine like terms:

   (3x + 2x + 2x) = 7x (5y - 3y - y) = y (-5x^2 + 10xy - 6x) = -5x^2 + 10xy - 6x (-3n) = -3n (12 + m + m) = 2m (12 - 6) = 6

4. Put all the terms back together:

   7x + y - 5x^2 + 10xy - 6x - 3n + 2m + 6

So, the simplified expression is:

7x + y - 5x^2 + 10xy - 6x - 3n + 2m + 6