Question

(5(2x - 3y)+7y=-52,12(3x +44)-6y=-4.​

Answer 1

Ответ:

теңдеу ма?бул жауап берындерш

Answer 2

It looks like you've provided a system of two linear equations with two variables, $x$ and $y$:

Equation 1: $5(2x - 3y) + 7y = -52$ Equation 2: $12(3x + 44) - 6y = -4$

To solve for the values of $x$ and $y$, we can use various methods such as substitution, elimination, or matrix methods. Let's solve this system using the elimination method:

Step 1: Simplify both equations:

Equation 1: $10x - 15y + 7y = -52$ Equation 2: $36x + 528 - 6y = -4$

Simplify further:

Equation 1: $10x - 8y = -52$ Equation 2: $36x - 6y = -532$

Step 2: Multiply Equation 1 by 3 and Equation 2 by 4 to make the coefficients of $y$ the same:

Equation 1 (multiplied by 3): $30x - 24y = -156$ Equation 2 (multiplied by 4): $144x - 24y = -2128$

Step 3: Subtract the modified Equation 1 from the modified Equation 2 to eliminate $y$:

$(144x - 24y) - (30x - 24y) = -2128 - (-156)$ $114x = -1972$

Step 4: Solve for $x$:

$x = \frac{-1972}{114} \approx -17.29$

Step 5: Substitute the value of $x$ into Equation 1 to solve for $y$:

$10x - 8y = -52$ $10(-17.29) - 8y = -52$ $-172.9 - 8y = -52$ $-8y = 120.9$ $y = \frac{120.9}{-8} \approx -15.11$

So, the solution to the system of equations is approximately $x \approx -17.29$ and $y \approx -15.11$.