Question

2 9/28+3 7/39-47 7/13

Answer 1

Ответ:

2 9/28+3 7/39-47 7/13=

2 9/28+3 7/39=5+9/28+7/39=5 547/1092

5 547/1092-47 7/13=6007/1092-618/13=-42 41/1092

Answer 2

Ответ: -42,03755.

Все расписано на фото.

Answer 3

To perform the calculations, let's convert the mixed numbers to improper fractions and then carry out the operations:

1. Convert mixed numbers to improper fractions:

• $2 \frac{9}{28}$ as an improper fraction is $\frac{(2 \times 28) + 9}{28} = \frac{65}{28}$
• $3 \frac{7}{39}$ as an improper fraction is $\frac{(3 \times 39) + 7}{39} = \frac{124}{39}$
• $47 \frac{7}{13}$ as an improper fraction is $\frac{(47 \times 13) + 7}{13} = \frac{616}{13}$

2. Perform the calculations:

$\frac{65}{28} + \frac{124}{39} - \frac{616}{13}$

To add and subtract fractions, they need to have the same denominator. The common denominator for 28, 39, and 13 is 21804.

Now let's convert all the fractions to have the same denominator:

• $\frac{65}{28} \times \frac{39}{39} = \frac{2535}{21804}$
• $\frac{124}{39} \times \frac{28}{28} = \frac{3472}{21804}$
• $\frac{616}{13} \times \frac{1684}{1684} = \frac{1037224}{21804}$

Now the equation becomes:

$\frac{2535}{21804} + \frac{3472}{21804} - \frac{1037224}{21804}$

Adding the numerators together and keeping the common denominator:

$\frac{2535 + 3472 - 1037224}{21804}$

Calculating the numerator:

$2535 + 3472 - 1037224 = -1031217$

So, the final fraction is:

$\frac{-1031217}{21804}$

This fraction cannot be simplified further, so the result is approximately:

$-47.2885$

Please double-check the calculations, as there's always a possibility of errors when performing manual calculations.