Question

5(3x-3y+3)-6(3x-2y-4)+3(x+y+1)

Answer 1

5(3x-3y+3)-6(3x-2y-4)+3(x+y+1)=0-15у+15+12у+24+3у+3=0+0+42=42

Answer 2

Ответ:

42

Пошаговое объяснение:

Распределяем 5 через скобки: 15х-15у+15-6(3х-2у-4)+3(х+у+1)

Распределяем -6 через скобки: 15х-15у+15-18х+12у+24+3(х+у+1)

Распределяем 3 через скобки: 15х-15у+15-18х+12у+24+3х+3у+3

Приводим подобные: 0+42=42

Answer 3

Let's simplify the given expression step by step:

5(3x - 3y + 3) - 6(3x - 2y - 4) + 3(x + y + 1)

First, apply the distributive property of multiplication over addition/subtraction within each set of parentheses:

= 5 * 3x - 5 * 3y + 5 * 3 - 6 * 3x + 6 * 2y + 6 * 4 + 3 * x + 3 * y + 3 * 1

Simplifying further:

= 15x - 15y + 15 - 18x + 12y + 24 + 3x + 3y + 3

Next, combine like terms:

= (15x - 18x + 3x) + (-15y + 12y + 3y) + (15 + 24 + 3)

= 0x - 0y + 42

Since 0x and 0y both equal zero, the simplified expression is:

= 42