Question

5х+2у=17 -10х+у=-29

Answer 1

ответ: (x,y)=(3,2)

1)  5x+2y=17  = 5x+2y=17

-10x+y=-29       y=-29+10x

5x+2(-29+10x)=17

5x-58+20x=17

25x=75

x=3

5*3+2y=17

15+2y=17

2y=17-15

y=1

   

Answer 2

It looks like you have a system of two linear equations with two variables, $x$ and $y$:

Equation 1: $5x + 2y = 17$ Equation 2: $-10x + y = -29$

To solve for $x$ and $y$, you can use various methods such as substitution, elimination, or matrix methods. Let's solve this system using the elimination method.

First, let's multiply the second equation by 2 to make the coefficients of $y$ in both equations match:

$2 \cdot (-10x + y) = 2 \cdot (-29)$ $-20x + 2y = -58$

Now, we have the following system of equations:

Equation 1: $5x + 2y = 17$ Equation 2: $-20x + 2y = -58$

Next, subtract Equation 2 from Equation 1 to eliminate the $y$ variable:

$(5x + 2y) - (-20x + 2y) = 17 - (-58)$ $5x + 2y + 20x - 2y = 75$ $25x = 75$

Now, divide both sides by 25:

$x = \frac{75}{25}$ $x = 3$

Now that we have the value of $x$, we can substitute it into either Equation 1 or Equation 2 to solve for $y$. Let's use Equation 2:

$-10x + y = -29$ $-10 \cdot 3 + y = -29$ $-30 + y = -29$

Add 30 to both sides:

$y = 1$

So, the solution to the system of equations is $x = 3$ and $y = 1$.