Question

3(х-2)=33 -2(х+4)=10-4х -4(х-2)-(5-3х)=14(5-9х)

Answer 1

Сори что не аккуратно тороплюсь

Answer 2

Let's solve each equation step by step:

1. $3(x - 2) = 33$: Distribute the 3 on the left side of the equation: $3x - 6 = 33$

Add 6 to both sides of the equation: $3x = 39$

Divide both sides by 3: $x = 13$

So, the solution to the first equation is $x = 13$.

2. $-2(x + 4) = 10 - 4x$: Distribute the -2 on the left side of the equation: $-2x - 8 = 10 - 4x$

Add 4x to both sides of the equation: $-2x + 4x - 8 = 10$

Combine like terms: $2x - 8 = 10$

Add 8 to both sides of the equation: $2x = 18$

Divide both sides by 2: $x = 9$

So, the solution to the second equation is $x = 9$.

3. $-4(x - 2) - (5 - 3x) = 14(5 - 9x)$: Distribute the -4 on the left side of the equation: $-4x + 8 - 5 + 3x = 70 - 126x$

Combine like terms on the left side: $-x + 3 = 70 - 126x$

Add x and 126x to both sides: $125x + 3 = 70$

Subtract 3 from both sides: $125x = 67$

Divide both sides by 125: $x = \frac{67}{125}$

So, the solution to the third equation is $x = \frac{67}{125}$.

To summarize:

1. $x = 13$
2. $x = 9$
3. $x = \frac{67}{125}$