Question

4sin^2(x)-12sin(x)=0

Answer 1

Пошаговое объяснение:

$></p> <p>sin(x)=3 ∉, так как |sin(x)|≤1</p> <p><em><strong>Ответ: x=πn.</strong></em></p> </div> <div class=$ 0 0

Answer 2

To solve the equation 4sin^2(x) - 12sin(x) = 0, we can factor out sin(x):

sin(x)(4sin(x) - 12) = 0

Now we have two factors: sin(x) = 0 and 4sin(x) - 12 = 0.

1. Setting sin(x) = 0: If sin(x) = 0, this means x can be any integer multiple of π since sin(x) = 0 at these values. So the general solutions for this part are: x = nπ, where n is an integer.

2. Setting 4sin(x) - 12 = 0: Adding 12 to both sides of the equation, we get: 4sin(x) = 12

Dividing both sides by 4: sin(x) = 3

Since the value of sin(x) cannot exceed 1, there are no real solutions for this equation.

In summary, the solutions to the equation 4sin^2(x) - 12sin(x) = 0 are: x = nπ, where n is an integer.