Question

(15x − 1)(6x + 1,2) = 0

Answer 1

Ответ:

Произведение равно 0, если один из множителей равен 0

Answer 2

Ответ:

x= 1/15;       x= -0.2

Пошаговое объяснение:

(15x − 1)(6x + 1,2) = 0

15x-1=0;     6x+1.2=0

15x=1;         6x= -1.2

x= 1/15;       x= -0.2

Answer 3

It looks like you have a quadratic equation and you want to solve for the value(s) of 'x' that satisfy it. The equation you provided is:

(15x - 1)(6x + 1.2) = 0

To solve for 'x', you can set each factor equal to zero and solve for 'x' in both cases:

1. 15x - 1 = 0 Add 1 to both sides: 15x = 1 Divide by 15: x = 1/15

2. 6x + 1.2 = 0 Subtract 1.2 from both sides: 6x = -1.2 Divide by 6: x = -0.2

So, the solutions for the equation are: x = 1/15 and x = -0.2