Question

11х^2-7х-10=х^2+9х-2​

Answer 1

Пошаговое объяснение:

11x^2-7x-10-x^2-9x+2=0

10x^2-16x-8=0

D=-16^2-4*10*(-8)=√256+320=√576=24

x1=(16+24)/(2*10)=40/20=2

x2=(16-24)/(2*10)=-8/20=-2/5=-0,4

Answer 2

It looks like you've provided an equation:

11x^2 - 7x - 10 = x^2 + 9x - 2

To solve for the value of 'x', we can start by simplifying the equation:

Subtracting x^2 and 9x from both sides:

11x^2 - x^2 - 7x - 9x - 10 = -2

Simplifying:

10x^2 - 16x - 10 = -2

Now, adding 2 to both sides:

10x^2 - 16x - 8 = 0

Dividing the entire equation by 2 to simplify further:

5x^2 - 8x - 4 = 0

Now, to solve this quadratic equation, you can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / 2a

In this case, the coefficients are: a = 5 b = -8 c = -4

Plugging these values into the formula:

x = (8 ± √((-8)^2 - 4 * 5 * -4)) / (2 * 5) x = (8 ± √(64 + 80)) / 10 x = (8 ± √144) / 10 x = (8 ± 12) / 10

This gives us two possible solutions for 'x':

1. x = (8 + 12) / 10 = 20 / 10 = 2
2. x = (8 - 12) / 10 = -4 / 10 = -0.4

So, the solutions for the equation are x = 2 and x = -0.4.