Question

3) 24а + 24c делится на 24, где аис — натуральные числа; 4) 18а + 45b + 99с делится на 9, где a, b, c — натуральные числа.​

Answer 1

Делится. К примеру а и с это 2(нат число же)

24*2=48

48+48= 96

96 делится на 24.  

Answer 2

1. To prove that 24a + 24c is divisible by 24, we can factor out 24 from both terms:

24a + 24c = 24(a + c)

Since a and c are natural numbers, (a + c) is also a natural number. Multiplying a natural number by 24 ensures that it is divisible by 24. Therefore, 24a + 24c is divisible by 24.

2. To prove that 18a + 45b + 99c is divisible by 9, we can factor out 9 from all three terms:

18a + 45b + 99c = 9(2a + 5b + 11c)

Again, since a, b, and c are natural numbers, (2a + 5b + 11c) is also a natural number. Multiplying a natural number by 9 ensures that it is divisible by 9. Therefore, 18a + 45b + 99c is divisible by 9.