Question

Log2 (корень x) + 1\2log2 (4/3)

Answer 1

Ответ:

вопще где задание??????!!!!

Answer 2

To simplify the expression "log2(√x) + 1/2 * log2(4/3)," you can use logarithm properties to combine the two terms:

1. Start with the expression: log2(√x) + 1/2 * log2(4/3).

2. Use the properties of logarithms to combine the terms:

   log2(√x) + log2((4/3)^(1/2))

3. Now, apply the square root property of exponents inside the logarithm:

   log2(√x) + log2(√(4/3))

4. You can combine the two logarithmic terms into a single logarithm using the product rule for logarithms:

   log2(√x * √(4/3))

5. Simplify the expression inside the logarithm by multiplying the square roots:

   log2(√(x * (4/3)))

6. Finally, you can further simplify by combining the square roots into a single square root:

   log2(√(4x/3))

So, the simplified expression is:

log2(√(4x/3))