Question

819. 1) 3(x - 2) 3) 5(y + 3) = 10;5) -4(x - 2) = -6;2) 6(z - 1) = 18;4) 3(2x - 7) = 9;6) 3(x - 5) = x + 3.​

Answer 1

Ответ:

3) у=-1

5) х= 3,5

2)z=4

4) x=5

6)x=9

Пошаговое объяснение:

3)5у+15=10

5у=-5

у=-1

5)-4(х-2)=-6

- 4х+8=-6

- 4х=-14

х= 3,5

2)6(z-1)=18

6z-6=18

6z=24

z=4

4)3(2x-7)=9

6x-21=9

6x=30

x=5

6)3(x-5)= x+3

3x-15=x+3

3x-x=3+15

2x=18

x=9

Answer 2

To solve these equations, you'll want to isolate the variables (x, y, and z) on one side of the equation. Here's how you can solve each of them step by step:

1. $3(x - 2)$ Start by distributing the 3 on the left side of the equation: $3x - 6 = 10$ Now, add 6 to both sides to isolate $3x$: $3x = 16$ Finally, divide both sides by 3 to solve for $x$: $x = \frac{16}{3}$

2. $6(z - 1) = 18$ Divide both sides by 6 to isolate $z - 1$: $z - 1 = 3$ Now, add 1 to both sides to solve for $z$: $z = 4$

3. $5(y + 3) = 10$ Divide both sides by 5 to isolate $y + 3$: $y + 3 = 2$ Subtract 3 from both sides to solve for $y$: $y = -1$

4. $3(2x - 7) = 9$ Start by distributing the 3 on the left side of the equation: $6x - 21 = 9$ Add 21 to both sides to isolate $6x$: $6x = 30$ Finally, divide both sides by 6 to solve for $x$: $x = 5$

5. $-4(x - 2) = -6$ Start by distributing the -4 on the left side of the equation: $-4x + 8 = -6$ Subtract 8 from both sides to isolate $-4x$: $-4x = -14$ Divide both sides by -4 to solve for $x$: $x = \frac{-14}{-4} = \frac{7}{2}$

6. $3(x - 5) = x + 3$ Start by distributing the 3 on the left side of the equation: $3x - 15 = x + 3$ Subtract $x$ from both sides to isolate $2x$: $2x - 15 = 3$ Add 15 to both sides to solve for $2x$: $2x = 18$ Finally, divide both sides by 2 to solve for $x$: $x = 9$

So, the solutions to the equations are:

1. $x = \frac{16}{3}$
2. $z = 4$
3. $y = -1$
4. $x = 5$
5. $x = \frac{7}{2}$
6. $x = 9$