Question

13/15z-(7/9+1/3z)=7целых2/9

Answer 1

$\frac{13}{15} z -(\frac{7}{9} +\frac{1}{3} z)=7\frac{2}{9} \\\\\frac{13z}{15} - \frac{7}{9} -\frac{z}{3} =\frac{65}{9} \\\\\frac{13z}{15} - \frac{7}{9} -\frac{z}{3}-\frac{65}{9}=0\\\\\frac{13z*3-7*5-15z-65*5}{45} =0\\\\39z-35-15z-325=0\\\\24z=260\\\\z=15$

Ответ: 15.

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Answer 2

To solve for the variable "z" in the equation:

$\frac{13}{15}z - \left(\frac{7}{9} + \frac{1}{3}z\right) = 7\frac{2}{9}$

Follow these steps:

Step 1: Distribute the negative sign to both terms inside the parentheses:

$\frac{13}{15}z - \frac{7}{9} - \frac{1}{3}z = 7\frac{2}{9}$

Step 2: To eliminate the fractions, find a common denominator for all the fractions. The common denominator here is 45:

Rewrite $\frac{13}{15}$ as $\frac{13}{15} \cdot \frac{3}{3} = \frac{39}{45}$

Rewrite $\frac{7}{9}$ as $\frac{7}{9} \cdot \frac{5}{5} = \frac{35}{45}$

Rewrite $\frac{1}{3}$ as $\frac{1}{3} \cdot \frac{15}{15} = \frac{15}{45}$

The equation becomes:

$\frac{39}{45}z - \frac{35}{45} - \frac{15}{45}z = 7\frac{2}{9}$

Step 3: Combine like terms on the left side of the equation:

$\left(\frac{39}{45} - \frac{15}{45}\right)z - \frac{35}{45} = 7\frac{2}{9}$

Simplify inside the parentheses:

$\frac{24}{45}z - \frac{35}{45} = 7\frac{2}{9}$

Step 4: Subtract $\frac{35}{45}$ from both sides of the equation:

$\frac{24}{45}z = 7\frac{2}{9} + \frac{35}{45}$

Step 5: Add the fractions on the right side:

$\frac{24}{45}z = 7\frac{2}{9} + \frac{35}{45} = 7\frac{2}{9} + \frac{7}{9} = \frac{9}{9}z = 8\frac{1}{9}$

Step 6: Divide both sides by $\frac{9}{9}$ to isolate "z":

$z = \frac{8\frac{1}{9}}{\frac{9}{9}}$

$z = 8\frac{1}{9}$

So, the solution to the equation is $z = 8\frac{1}{9}$