Question

..1) y = (3x - 1) (2x + 5);​

Answer 1

Ответ:

вроде бы так

Пошаговое объяснение:

y=6x^2+15x-2x-5

y=6x^2+13x-5

y возьмем за 0 и получаем кв. уравнение

6х^2+13x-5=0

D=13^2-4*6*(-5)=289=17^2

X(1)= (-13+17)/12=4/12=1/3

X(2)= (-13-17)/12=-2,5

Answer 2

It looks like you've provided an algebraic expression:

y = (3x - 1)(2x + 5)

This is a quadratic expression, and you can simplify it or perform various operations with it, depending on what you need. If you have a specific question or operation you'd like to perform with this expression, please let me know, and I'll be happy to assist you further.