Question

X2-8x+7=? y2(y-7) (y+2)=? a3-8=?

Answer 1

Ответ:

(x-1)  (x-7),  2) y4-5y3-14y2,  3) (a-2) (a2+2a+4)

Пошаговое объяснение:

Answer 2

$x^2-8x+7=x^2-x-7x+7=x(x-1)-7(x-1)=\bold{(x-1)(x-7)}\\y^2(y-7)(y+2)=(y^3-7y^2)(y+2)=\bold{y^4+2y^3-7y^3-14y^2}\\a^3-8=a^3-2^3=(a-2)(a^2+a\cdot2+2^2)=\bold{(a-2(a^2+2a+4)}$

__________

Использованные формулы при решении:

$a^3-b^3=(a-b)(a^2+ab+b^2)$

Answer 3

Let's simplify each expression one by one:

1. x^2 - 8x + 7:

   To simplify this quadratic expression, we can factor it:

   x^2 - 8x + 7 = (x - 7)(x - 1)

2. y^2(y - 7)(y + 2):

   To simplify this expression, you can first expand it:

   y^2(y - 7)(y + 2) = y^2(y^2 - 5y - 14)

3. a^3 - 8:

   This expression is a cube of a minus 8. We can write it as:

   a^3 - 8 = (a - 2)(a^2 + 2a + 4)

So, here are the simplified forms of the expressions:

1. x^2 - 8x + 7 = (x - 7)(x - 1)
2. y^2(y - 7)(y + 2) = y^4 - 5y^3 - 14y^2
3. a^3 - 8 = (a - 2)(a^2 + 2a + 4)