Question

Cos( 3x + n:6 ) = -1 ​

Answer 1

Ответ:

решение смотри на фотографии

Answer 2

Ответ:

3x+pi/6 = pi + 2pi*k (k принадлежит множеству целых)

3x = 5pi/6 + 2pi*k

x = 5pi/18 +2pi/3*k

Answer 3

To solve the equation $\cos(3x + \frac{n}{6}) = -1$, we'll first find the values of $x$ that satisfy this equation.

The cosine function has a period of $2\pi$, meaning that $\cos(\theta) = \cos(\theta + 2\pi k)$ for any integer $k$.

In this case, we want to find $x$ such that $\cos(3x + \frac{n}{6}) = -1$. Since the cosine function has a period of $2\pi$, we can write:

$3x + \frac{n}{6} = (2k + 1)\pi$

where $k$ is an integer.

Now, we'll solve for $x$:

$3x = (2k + 1)\pi - \frac{n}{6}$

$x = \frac{(2k + 1)\pi}{3} - \frac{n}{18}$

This is the general solution for $x$ that satisfies $\cos(3x + \frac{n}{6}) = -1$, where $k$ can be any integer.