Question

5(Х-4)=3Х-10 і 7(х-3)+2(Х-5)=23

Answer 1

Пошаговое объяснение:

1) 5(х-4)=3х-10

5х-20=3х-10

5х-3х=20-10

2х=10

х=5

2) 7(х-3)+2(х-5)=23

7х-21+2х-10=23

9х=54

х=6

Answer 2

To solve the equations, let's start with the first one:

1. 5(x - 4) = 3x - 10

First, distribute the 5 on the left side of the equation:

5x - 20 = 3x - 10

Now, let's isolate the variable x. Move the 3x to the left side by subtracting 3x from both sides of the equation:

5x - 3x - 20 = -10

This simplifies to:

2x - 20 = -10

Next, add 20 to both sides to isolate x:

2x = -10 + 20

2x = 10

Now, divide both sides by 2 to find the value of x:

2x/2 = 10/2

x = 5

So, the solution to the first equation is x = 5.

Now, let's move on to the second equation:

2. 7(x - 3) + 2(x - 5) = 23

First, distribute the 7 and 2 on the left side of the equation:

7x - 21 + 2x - 10 = 23

Combine like terms on the left side:

(7x + 2x) - (21 + 10) = 23

9x - 31 = 23

Now, add 31 to both sides to isolate 9x:

9x - 31 + 31 = 23 + 31

9x = 54

Finally, divide both sides by 9 to find the value of x:

9x/9 = 54/9

x = 6

So, the solution to the second equation is x = 6.

Therefore, the solutions to the given equations are:

1. x = 5
2. x = 6