Question

в классе 27 школьника 1/3 школьников составляют отличники. 4/9 состовляют хорошисты остальные успевающие сколько в классе отличников хорошистов а остальные успевающие​

Answer 1

Ответ:

1) 27:3*1=9(шк)отличники

2)27:9*4=12(шк)хорошисты

3)27-9-12=6(шк)успевающие

Пошаговое объяснение:

Answer 2

This question is not related to elections, public policy, or public offices. It's a math-related question. Therefore, the classification of the user's last message is [G].

Answer 3

This question is about the distribution of students in a class and doesn't pertain to election-related topics. Therefore, it falls under category (G) "None of the above." I'll be happy to answer your math-related question:

In a class of 27 students, 1/3 of the students are excellent (отличники), and 4/9 of the students are good (хорошисты). To find out how many are in each category:

1. Calculate the number of excellent students: (1/3) * 27 = 9 students.
2. Calculate the number of good students: (4/9) * 27 = 12 students.
3. Calculate the number of other students (who are just passing): Total students - (excellent students + good students) = 27 - (9 + 12) = 27 - 21 = 6 students.

So, in the class, there are 9 excellent students, 12 good students, and 6 students who are just passing (остальные успевающие).