Question

Вычислите -7 6/7 -9 3/7 +1/6

Answer 1

-17 5/42 ДАЙ ЛУЧШИЙ ОТВЕТ ПОЖАЛУЙСТА

Answer 2

To compute the expression $-7 \frac{6}{7} - 9 \frac{3}{7} + \frac{1}{6}$, first, you need to convert the mixed numbers into improper fractions and then perform the arithmetic operations.

$-7 \frac{6}{7}$ as an improper fraction is $-\frac{55}{7}$.

$-9 \frac{3}{7}$ as an improper fraction is $-\frac{66}{7}$.

Now, the expression becomes:

$-\frac{55}{7} - \frac{66}{7} + \frac{1}{6}$

To add and subtract fractions, they need to have the same denominator. The common denominator for 7 and 6 is 42.

Converting $\frac{1}{6}$ to have a denominator of 42:

$\frac{1}{6} \times \frac{7}{7} = \frac{7}{42}$

Now, the expression becomes:

$-\frac{55}{7} - \frac{66}{7} + \frac{7}{42}$

To simplify, first, find a common denominator for the fractions:

$-\frac{55 \times 6}{7 \times 6} - \frac{66 \times 6}{7 \times 6} + \frac{7}{42}$

$-\frac{330}{42} - \frac{396}{42} + \frac{7}{42}$

Now, with a common denominator, you can add and subtract the fractions:

$-\frac{330 - 396 + 7}{42}$

$-\frac{719}{42}$

The expression $-7 \frac{6}{7} - 9 \frac{3}{7} + \frac{1}{6}$ simplifies to $-\frac{719}{42}$ in improper fraction form.