Question

(5m^2+14m-7)+(m^2+7m)=​

Answer 1

(5m²+14m-7)+(m²+7m)=5m²+14m-7+m²+7m=6m²+21m-7

Answer 2

To simplify the given expression, we'll combine like terms by adding the coefficients of the same degree of $m$:

$5m^2 + 14m - 7 + m^2 + 7m$

First, combine the $m^2$ terms:

$5m^2 + m^2 = 6m^2$

Next, combine the $m$ terms:

$14m + 7m = 21m$

Now, combine the constant terms:

$-7$ (from $5m^2 + 14m - 7$) remains as it is.

Putting it all together, we get:

$6m^2 + 21m - 7$