Question

-2(6х+3у)+1=у-3 11-4(х-у)=у-2​

Answer 1

Ответ:

Пошаговое объяснение:

Answer 2

Let's solve the system of equations:

1. $-2(6x + 3y) + 1 = y - 3$
2. $11 - 4(x - y) = y - 2$

Let's simplify each equation step by step:

Equation 1: $-2(6x + 3y) + 1 = y - 3$

Distribute the -2: $-12x - 6y + 1 = y - 3$

Add 6y to both sides: $-12x + 1 = 7y - 3$

Add 3 to both sides: $-12x + 4 = 7y$

Divide by 7: $y = \frac{-12x + 4}{7}$

Equation 2: $11 - 4(x - y) = y - 2$

Distribute the -4: $11 - 4x + 4y = y - 2$

Subtract y from both sides: $11 - 4x + 3y = -2$

Subtract 11 from both sides: $-4x + 3y = -13$

Now, we have a system of two equations:

$y = \frac{-12x + 4}{7}$ $-4x + 3y = -13$

Now, you can substitute the expression for y from the first equation into the second equation and solve for x:

$-4x + 3\left(\frac{-12x + 4}{7}\right) = -13$

After finding the value of x, you can substitute it back into either of the original equations to find the corresponding y-value.