Question

(2x-1)(3x+2)=6(x²-x+2)​

Answer 1

Ответ:

Пошаговое объяснение:

Answer 2

To solve the quadratic equation $(2x-1)(3x+2) = 6(x^2 - x + 2)$, we can start by expanding and simplifying both sides.

Expand the expressions on both sides of the equation:

$(2x-1)(3x+2) = 6(x^2 - x + 2)$

$6x^2 + 4x - 3x - 2 = 6x^2 - 6x + 12$

Combine like terms:

$6x^2 + x - 2 = 6x^2 - 6x + 12$

Now, subtract $6x^2$ from both sides to simplify the equation:

$x - 2 = -6x + 12$

Add $6x$ to both sides:

$7x - 2 = 12$

Add 2 to both sides:

$7x = 14$

Divide by 7:

$x = 2$

So, the solution to the equation is $x = 2$. You can check this solution by substituting $x = 2$ back into the original equation to make sure both sides are equal.