Question

1200÷28×16-680=??27×15÷81+66=???? Пж помогите ​

Answer 1

Ответ:

1. Ответ: 6,4

2. Ответ: 71

Пошаговое объяснение:

1200÷28×16-680=?

1) 1200/28=42.9 (Получается бесконечная дробь, округляем)

2) 42.9*16=686.4

3) 686.4-680=6,4

или

1200/28 = 300/7

1) 300/7 * 16/1 = 4800/7

2) 4800/7 - 680/1 = (4800-4760)/7 = 40/7

Ответ: 6,4

27×15÷81+66=?

1) 27*15=405

2) 405/81=5

3) 5+66=71

Ответ: 71

Answer 2

To solve the given equations, let's break them down step by step:

1. 1200 ÷ 28 × 16 - 680 = ?? To solve this equation, we need to follow the order of operations, which is commonly known as PEMDAS (Parentheses, Exponents, Multiplication and Division, and Addition and Subtraction).

First, let's perform the division: 1200 ÷ 28 = 42.85714285714286 (rounded to 14 decimal places).

Next, let's perform the multiplication: 42.85714285714286 × 16 = 685.7142857142857 (rounded to 14 decimal places).

Finally, let's perform the subtraction: 685.7142857142857 - 680 = 5.7142857142857 (rounded to 14 decimal places).

Therefore, the solution to the first equation is 5.7142857142857.

2. 27 × 15 ÷ 81 + 66 = ?? Again, let's follow the order of operations.

First, let's perform the multiplication: 27 × 15 = 405.

Next, let's perform the division: 405 ÷ 81 = 5.

Finally, let's perform the addition: 5 + 66 = 71.

Therefore, the solution to the second equation is 71.

So, the solutions to the given equations are: - 1200 ÷ 28 × 16 - 680 = 5.7142857142857 - 27 × 15 ÷ 81 + 66 = 71.

I hope this helps! Let me know if you have any further questions.