
Площадь прямоугольника 360см в квадрате размер одной из сторон - 30см. Найди площадь квадрата,
периметр которого равен периметру прямоугольника. Помогите срочно!!!

Ответы на вопрос

Ответ:
1)360:30=12см это ширина
2)(30+12)×2=84см это периметр
3)84:4=21см это длина квадрата
4)21×21=441см площадь квадрата



Calculation of Rectangle Area and Side Lengths
To find the area of a rectangle, we multiply the length by the width. In this case, the area of the rectangle is given as 360 cm², and one of the side lengths is 30 cm. Let's calculate the other side length.Let the length of the rectangle be L and the width be W. We know that L * W = 360 cm² and one of the side lengths is 30 cm. We can set up the following equation:
L * 30 = 360
Solving for L, we divide both sides of the equation by 30:
L = 360 / 30 = 12 cm
Therefore, the length of the rectangle is 12 cm.
Calculation of Rectangle Perimeter
The perimeter of a rectangle is the sum of all its side lengths. To find the perimeter of the given rectangle, we can use the formula:Perimeter = 2 * (Length + Width)
Substituting the values we know, the perimeter of the rectangle is:
Perimeter = 2 * (12 cm + 30 cm) = 2 * 42 cm = 84 cm
Calculation of Square Area and Side Length
Now, we need to find the area and side length of a square with the same perimeter as the rectangle.The perimeter of the square is also 84 cm, so each side length of the square is equal to 84 cm divided by 4 (since a square has four equal sides):
Side Length = Perimeter / 4 = 84 cm / 4 = 21 cm
To find the area of the square, we square the side length:
Area = Side Length * Side Length = 21 cm * 21 cm = 441 cm²
Therefore, the area of the square with a perimeter equal to the perimeter of the given rectangle is 441 cm².
Summary: - The length of the rectangle is 12 cm, and one of the side lengths is 30 cm. - The perimeter of the rectangle is 84 cm. - The side length of the square with the same perimeter is 21 cm. - The area of the square is 441 cm².
I hope this helps! Let me know if you have any further questions.


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