Question

Срочно помогитееее пж. Сплав, который состоит из олова и цинка, массы которых относятся как 9:8. Масса сплава 2 кг 380 г. Сколько в этом сплаве олова и цинка?

Answer 1

1 метод
а)9+8=17частей-всего.
2550:17=150грамм-одна часть.
150*8=1200грамм(1кг 200г)-цинка.

б)11+7=18частей-всего.
1440:18=80грамм-одна часть.
80*11=880грамм-олова.
2 метод
Сплав состоит из меди и цинка, массы которых относятся как 9:8. Масса сплава 2 кг 550 г. Сколько в этом сплаве цинка?

1) 9+8=17 частей
2) 2550:17=150 гр масса 1 доли сплава
3)150*8=1200 грамм либо 1 кг 200 гр масса цинка в сплаве

Answer 2

Calculation of the Mass of Tin and Zinc in the Alloy

To determine the mass of tin and zinc in the alloy, we can use the given ratio of their masses and the total mass of the alloy.

Given: - Ratio of tin to zinc mass: 9:8 - Total mass of the alloy: 2 kg 380 g

To find the mass of tin and zinc, we can set up the following equations:

Let x be the mass of tin in the alloy, and y be the mass of zinc in the alloy.

Equation 1: x + y = 2 kg 380 g (total mass of the alloy) Equation 2: x/y = 9/8 (ratio of tin to zinc mass)

To solve these equations, we can use substitution or elimination.

Let's use substitution to solve the equations:

From Equation 2, we can rewrite it as x = (9/8)y.

Substituting this value of x into Equation 1, we get:

(9/8)y + y = 2 kg 380 g

Combining like terms:

(17/8)y = 2 kg 380 g

To solve for y, we can multiply both sides of the equation by 8/17:

y = (2 kg 380 g) * (8/17)

Calculating the value of y:

y = 0.941 kg

Now, we can substitute the value of y back into Equation 2 to find the value of x:

x = (9/8) * 0.941 kg

Calculating the value of x:

x = 1.058 kg

Therefore, in the given alloy with a total mass of 2 kg 380 g, the mass of tin is approximately 1.058 kg and the mass of zinc is approximately 0.941 kg.

Note: The calculated values are approximate due to rounding.