Question

3 Реши обратные задачи. правились на стадион. Расстояние между домами мальчи- а) Арман и Серик Одновременно вышли из своих домов и на - 200 м. Арман живёт дальше, скорость его движения - 175 м/мин. С какой скоростью шёл Серик, если Арман Догнат КОВ 2. его через 2 минуты? и, = ? м/мин tecтр. 2 мин и, = 175 м/мин + Стадион Дом С. Дом А. S = 200 м уравнением​

Answer 1

Ответ:

Решим уравнением

(175-х)×2=200

175-х=200:2

175-х=100

х=175-100 to

х=76(м/мин)-скорость Серик

(175-75)×2=200

175-75=100

100×2=200

200=200

Ответ: скорость Черника 75 м/мин

обратная задача

надо узнать S

1) 175-75=100

S=V×t

2)100×2=200(м)-S

Answer 2

Problem Analysis

We are given that Arman and Serik start from their respective homes and meet at a stadium. The distance between their homes is 200 meters. Arman starts from a home that is farther away and walks at a speed of 175 m/min. We need to find the speed at which Serik is walking if Arman catches up to him in 2 minutes.

Solution

Let's assume that Serik's speed is x m/min. Since Arman catches up to Serik in 2 minutes, we can set up the following equation based on the distance and time traveled by both:

Distance traveled by Arman = Distance traveled by Serik

Arman's distance = 200 meters (since he starts farther away) Serik's distance = x m/min * 2 min

Setting up the equation:

200 = x * 2

Simplifying the equation:

200 = 2x

Dividing both sides by 2:

100 = x

Therefore, Serik is walking at a speed of 100 m/min.

Answer

Serik is walking at a speed of 100 m/min.