Question

В первой урне находится 6 черных и 4 белых шара, во второй- 3 черных и 3 белых шаров. Из каждой урны извлекают по одному шару. Какова вероятность того, что оба шара окажутся белыми?

Answer 1

Ответ:

Вероятность вынуть белый шар из 1 урны Р1=4/(6+4)=0,4. Вероятность вынуть белый шар из 2 урны Р2=7/(7+5)=0,5833. Вероятность, что оба шара белые равна произведению независимых событий Р=Р1*Р2=0,4*0,5833=0,2333.

Answer 2

Problem Analysis

We have two urns: the first urn contains 6 black and 4 white balls, and the second urn contains 3 black and 3 white balls. We need to find the probability that both balls drawn, one from each urn, are white.

Solution

To find the probability, we need to calculate the probability of drawing a white ball from the first urn and a white ball from the second urn, and then multiply these probabilities together.

Let's calculate the probability step by step:

1. Probability of drawing a white ball from the first urn: - The first urn contains a total of 10 balls (6 black + 4 white). - The probability of drawing a white ball from the first urn is therefore 4/10.

2. Probability of drawing a white ball from the second urn: - The second urn contains a total of 6 balls (3 black + 3 white). - The probability of drawing a white ball from the second urn is therefore 3/6.

3. Probability of drawing a white ball from both urns: - To find the probability of both events happening, we multiply the probabilities together. - So the probability of drawing a white ball from both urns is (4/10) * (3/6).

Therefore, the probability that both balls drawn will be white is (4/10) * (3/6) = 2/15.

Answer

The probability that both balls drawn, one from each urn, will be white is 2/15.