Question

3. Доктор Айболит хочет навестить и корову, и волчицу, и жучка, и червячка. Все четверо живут вдоль одной прямой дороги. орлы готовы утром доставить Айболита к первому пациенту, а вечером забрать от последнего, но три промежуточных перехода ему придётся сделать пешком. Если Айболи начнёт с коровы, то длина его кратчайшего маршрута составит 6 км, если с волчицы 7 км, а если с жучка — 8 км. Нарисуйте, как могли располагаться домики коровы, волчицы, жучка и червяч- ка (достаточно одного примера расположения; не забудьте указать расстояния между домиками). [4 балла)

Answer 1

Ответ:

Смотри картинку

Answer 2

Arrangement of the Animals' Homes and Calculation of Distances

To solve this problem, we need to consider the distances between the animals' homes and the distances between the animals themselves.

Let's start by considering the distances between the animals' homes.

If we assume that the cow's home is at the beginning of the road, the wolf's home is 6 km from the cow's home, the beetle's home is 7 km from the wolf's home, and the worm's home is 8 km from the beetle's home, we can visualize their arrangement.

Now, let's calculate the distances between the animals themselves based on this arrangement.

The cow's home is at the beginning of the road, so the wolf's home is 6 km from the cow's home, the beetle's home is 7 km from the wolf's home, and the worm's home is 8 km from the beetle's home.

This arrangement satisfies the given conditions and the distances between the animals' homes.

Therefore, the arrangement of the animals' homes and the distances between them can be visualized as follows:

Cow's Home (0 km) ----- Wolf's Home (6 km) ----- Beetle's Home (13 km) ----- Worm's Home (21 km)