Question

В соревновании принимают участие 29 спортсменов. С помощью жребия выбирают двух спортсменов. Какова вероятность того, что спортсмен К., участвующий в соревновании, будет выбран?Срочно!!!Помогите, пожалуйста!!!

Answer 1

Ответ:

Пошаговое объяснение:

1)

Вероятность того, что спортсмен К. будет выбран при первом голосовании:

P(A) = 1 / n = 1 / 29

2)

Вероятность того, что спортсмен К. будет выбран при втором  голосовании:

P(B) = 1 / (n - 1) = 1 / 28

3)

По правилу сложения вероятностей:

P(C) = P(A) + P(B) = 1 /29 + 1/28 = 57 / 812   или

P(C) ≈ 0,07

Answer 2

Probability of Sporstman K being chosen

To calculate the probability of Sporstman K being chosen, we need to determine the total number of possible outcomes and the number of favorable outcomes.

In this case, there are 29 sportsmen participating in the competition, and two of them will be chosen through a draw. Therefore, the total number of possible outcomes is the number of ways to choose 2 sportsmen out of 29, which can be calculated using the combination formula:

Total number of possible outcomes = C(29, 2)

To calculate the number of favorable outcomes, we need to determine the number of ways Sporstman K can be chosen. Since only two sportsmen will be chosen, Sporstman K can either be one of the chosen sportsmen or not. Therefore, the number of favorable outcomes is 2: either Sporstman K is chosen or not.

Number of favorable outcomes = 2

Now, we can calculate the probability of Sporstman K being chosen by dividing the number of favorable outcomes by the total number of possible outcomes:

Probability of Sporstman K being chosen = Number of favorable outcomes / Total number of possible outcomes

Let's calculate the probability:

Probability of Sporstman K being chosen = 2 / C(29, 2)

To calculate the combination C(29, 2), we can use the formula:

C(n, r) = n! / (r! * (n-r)!)

where n is the total number of items and r is the number of items chosen.

Let's calculate the probability using the given information:

Probability of Sporstman K being chosen = 2 / (29! / (2! * (29-2)!))

Using the formula, we can simplify the expression:

Probability of Sporstman K being chosen = 2 / (29! / (2! * 27!))

Now, let's calculate the probability using the given information:

Probability of Sporstman K being chosen = 2 / (29 * 28 / (2 * 1))

Probability of Sporstman K being chosen = 2 / (406 / 2)

Probability of Sporstman K being chosen = 2 / 203

Therefore, the probability of Sporstman K being chosen is 1/203.

Please note that the above calculation assumes that the draw is fair and each sportsman has an equal chance of being chosen.