Question

В первой коробке 3 белых и 4 черных шаров, во второй коробке 2 белых и 3 черных. С первого во второй ящик переложили 3 шара. Вычислить вероятность того, что из второй коробке, 3 шары будут белые.

Answer 1

Ответ:

там новоерное 3 белых или же 1 белый и два черных

Пошаговое объяснение:

Answer 2

Problem Analysis

We have two boxes, Box 1 and Box 2. Box 1 contains 3 white balls and 4 black balls, while Box 2 contains 2 white balls and 3 black balls. We transfer 3 balls from Box 1 to Box 2. We need to calculate the probability that all 3 balls in Box 2 are white.

Solution

To solve this problem, we can use the concept of conditional probability. Let's break down the problem step by step.

Step 1: Calculate the probability of selecting 3 white balls from Box 1 and transferring them to Box 2. - The probability of selecting a white ball from Box 1 is 3/7 (since there are 3 white balls out of a total of 7 balls in Box 1). - After transferring the first white ball, the probability of selecting another white ball from Box 1 is 2/6 (since there are now 2 white balls left out of a total of 6 balls in Box 1). - Similarly, after transferring the second white ball, the probability of selecting the third white ball from Box 1 is 1/5 (since there is now 1 white ball left out of a total of 5 balls in Box 1). - Therefore, the probability of selecting 3 white balls from Box 1 and transferring them to Box 2 is: (3/7) * (2/6) * (1/5) = 1/35.

Step 2: Calculate the probability of selecting 3 balls from Box 2 and all of them being white. - After transferring 3 balls from Box 1 to Box 2, Box 2 contains 5 balls in total (2 white balls and 3 black balls). - The probability of selecting a white ball from Box 2 on the first draw is 2/5 (since there are 2 white balls out of a total of 5 balls in Box 2). - After transferring the first white ball, the probability of selecting another white ball from Box 2 is 1/4 (since there is now 1 white ball left out of a total of 4 balls in Box 2). - Similarly, after transferring the second white ball, the probability of selecting the third white ball from Box 2 is 0/3 (since there are no white balls left in Box 2). - Therefore, the probability of selecting 3 balls from Box 2 and all of them being white is: (2/5) * (1/4) * (0/3) = 0.

Answer

The probability that all 3 balls in Box 2 will be white after transferring 3 balls from Box 1 is 0.