Question

Tg (2п+a)*sin(3п/2-а)=sina

Answer 1

надеюсь помог..... хы.

Answer 2

To solve the equation Tg((2π+a)*sin(3π/2-a)) = sin(a), let's go step by step:

1. Expand the trigonometric expression: Tg(2πsin(3π/2) + asin(3π/2) - a*sin(a))

2. Simplify the trigonometric values: Tg(0 + (-a) - a*sin(a))

3. Rearrange the equation: Tg(-2a - a*sin(a)) = sin(a)

4. Substitute Tg(x) with sin(x)/cos(x): sin(-2a - asin(a))/cos(-2a - asin(a)) = sin(a)

5. Multiply both sides by cos(-2a - asin(a)): sin(-2a - asin(a)) = sin(a)cos(-2a - asin(a))

6. Apply the identity sin(α) = cos(π/2 - α): cos(π/2 - (2a + a*sin(a))) = sin(a)cos(-2a - asin(a))

7. Simplify the left side: cos(π/2 - 2a - a*sin(a)) = sin(a)cos(-2a - asin(a))

Now, this equation cannot be solved algebraically in a general sense. However, you can approximate the solution numerically using methods such as iteration or numerical solvers.