Question

X² + y² = 4 y+ x = 0​

Answer 1

Надеюсь здесь ясно,,,,.

Answer 2

To solve the given system of equations:

Equation 1: x² + y² = 4 Equation 2: y + x = 0

We can rearrange Equation 2 to express x in terms of y:

x = -y

Now, substitute this value of x in Equation 1:

(-y)² + y² = 4 y² + y² = 4 2y² = 4 y² = 2 y = ±√2

Substitute the values of y back into Equation 2 to find the corresponding values of x:

For y = √2: x = -√2

For y = -√2: x = √2

So, the solutions to the system of equations are: (x, y) = (-√2, √2) and (√2, -√2)