Question

72-(a+16)=7 n:4+24=32 54-49:c=47

Answer 1

Решение на фото …………

Answer 2

To solve the given equations, let's break them down one by one:

1. 72 - (a + 16) = 7

First, let's simplify the expression inside the parentheses by combining "a" and "16":

72 - (a + 16) = 7 72 - a - 16 = 7

Now, let's combine like terms:

56 - a = 7

To isolate "a," we can subtract 56 from both sides:

56 - a - 56 = 7 - 56 -a = -49

Finally, multiplying both sides by -1 gives us the value of "a":

a = 49

2. n:4 + 24 = 32

Let's simplify the expression on the left side first:

n/4 + 24 = 32

To isolate "n," we can subtract 24 from both sides:

n/4 + 24 - 24 = 32 - 24 n/4 = 8

To get "n" by itself, we multiply both sides by 4:

4 * (n/4) = 4 * 8 n = 32

3. 54 - 49:c = 47

Let's simplify the equation first:

54 - 49/c = 47

To eliminate the fraction, we can multiply both sides by "c":

c * (54 - 49/c) = c * 47

Now, distribute "c" to each term inside the parentheses:

54c - 49 = 47c

To isolate "c," let's move all terms involving "c" to one side:

54c - 47c = 49

Simplifying further:

7c = 49

Finally, divide both sides by 7 to solve for "c":

7c/7 = 49/7 c = 7

Therefore, the solutions to the given equations are: a = 49 n = 32 c = 7