Question

S=54a Ширина-60 м P-? (1a=100м²)

Answer 1

Ответ:

р=(60+54)*2=228

надеюсь правильно

Answer 2

To find the perimeter (P) of a shape with a width of 60 meters and an area of 54a, where 1a represents 100 square meters, we need to determine the length of the shape.

We know that the area (A) of a rectangle is calculated by multiplying its length (L) and width (W):

A = L * W

In this case, the area is given as 54a, which means:

54a = L * 60

To find the value of L, we need to divide both sides of the equation by 60:

54a / 60 = L

Simplifying the expression:

9a / 10 = L

Now that we have the length, we can calculate the perimeter (P) of the rectangle by using the formula:

P = 2 * (L + W)

Substituting the values:

P = 2 * (9a / 10 + 60)

Simplifying further:

P = 2 * (9a / 10) + 2 * 60

P = (18a / 10) + 120

Therefore, the perimeter (P) of the shape is (18a / 10) + 120.