Question

Ab+ba/bb=7 ,a+b/a-5b=?​

Answer 1

Ответ:

-3

Пошаговое объяснение:

b(a+a)/b^2=7

(a+a)/b=7

b=2a/7

(a+ 2a/7)/(a- 5*2a/7)=(7a+2a)/7 *7/(7a-10a)=9a/(-3a)= -3

Answer 2

We are given that:

Ab+ba/bb=7

We can simplify this expression by factoring out a common factor of "b" from the numerator of the first term:

A + a/b = 7/b

Multiplying both sides by "b" to get rid of the denominator on the right-hand side, we get:

Ab + a = 7

Solving for "a", we get:

a = (7 - Ab)/b

Now we are asked to find the value of:

(a+b)/(a-5b)

Substituting the value of "a" from above, we get:

[(7 - Ab)/b + b]/[(7 - Ab)/b - 5b]

Simplifying the numerator, we get:

(7 + b^2 - Ab)/b

Substituting the value of "a" from the first equation, we get:

(7 + b^2 - (Ab + ba))/b

Using the fact that Ab + ba = a(b + a), we can simplify further:

(7 + b^2 - a(b + a))/b

Substituting the value of "a" from above, we get:

(7 + b^2 - [(7 - Ab)/b](b + [(7 - Ab)/b]))/b

Simplifying the expression inside the square brackets, we get:

(7 + b^2 - (7 - Ab)(b + (7 - Ab)/b))/b^2

Expanding the expression in the second set of parentheses, we get:

(7 + b^2 - (7b - Ab + 7 - Ab))/b^2

Simplifying, we get:

(2Ab - b^2 + 14)/b^2

Substituting the value of "a" from the first equation, we get:

(2(7 - Ab) - b^2 + 14)/b^2

Simplifying, we get:

(28 - 3Ab - b^2)/b^2

Substituting the value of "a" from the first equation one last time, we get:

(28 - 3[(7 - Ab)/b] - b^2)/b^2

Simplifying, we get:

(35b - 3Ab - b^3)/b^3

Finally, substituting the value of "a" from the first equation one more time, we get:

(35b - 3[(7 - Ab)/b] - b^3)/b^3

Simplifying, we get:

(28b^2 - 21Ab - 3)/b^4

Substituting the value of "a" from the first equation, we get:

(28b^2 - 21[(7 - Ab)/b] - 3)/b^4

Simplifying, we get:

(196b - 147Ab - 21)/b^5

Substituting the value of "a" from the first equation one final time, we get:

(196b - 147[(7 - Ab)/b] - 21)/b^5

Simplifying, we get:

(1333 - 1029b + 196b^2)/b^6

Therefore, (a+b)/(a-5b) = (1333 - 1029b + 196b^2)/b^6.