
1) (х-18)-73=39 и 24+(у-52)=81 2) (65-х)+14=51 и (у+16)+37= 284 20балов


Ответы на вопрос

Х-18=112
Х=112+18
Х=130
У-52=81-24
У-52=57
У=57+52
У=109
65-Х=51-14
65-х=37
×=65-37
×=28
У+16=284-37
У+16=247
У=247-16
У=231



To solve these equations:
- (х-18)-73=39
First, simplify the left side of the equation by combining like terms: х - 18 - 73 = 39 х - 91 = 39
Next, add 91 to both sides of the equation: х - 91 + 91 = 39 + 91 х = 130
So the solution to the first equation is х = 130.
For the second part of the problem:
24 + (у-52) = 81
First, simplify the left side of the equation by combining like terms: у - 52 + 24 = 81 у - 28 = 81
Next, add 28 to both sides of the equation: у - 28 + 28 = 81 + 28 у = 109
So the solution to the second equation is у = 109.
- (65-х)+14=51
First, simplify the left side of the equation by combining like terms: 65 - х + 14 = 51 79 - х = 51
Next, subtract 79 from both sides of the equation: 79 - х - 79 = 51 - 79 -х = -28
Finally, multiply both sides of the equation by -1 to isolate х: -1(-х) = -1(-28) х = 28
So the solution to the first equation is х = 28.
For the second part of the problem:
(у+16)+37= 284
First, simplify the left side of the equation by combining like terms: у + 16 + 37 = 284 у + 53 = 284
Next, subtract 53 from both sides of the equation: у + 53 - 53 = 284 - 53 у = 231
So the solution to the second equation is у = 231.
Therefore, the solutions to both equations are х = 28 and у = 231, and the student earns 20 points.


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